Question
a. $\frac{x-1}{x+2}+\frac{x+2}{x-1}$b. $\frac{x-1}{x+2} \cdot \frac{x+2}{x-1}$
Step 1
We can do this by finding a common denominator for the two fractions, which is $(x+2)(x-1)$. So, we have: \[\frac{x-1}{x+2}+\frac{x+2}{x-1} = \frac{(x-1)^{2}}{(x+2)(x-1)} + \frac{(x+2)^{2}}{(x+2)(x-1)}\] Show more…
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