00:02
Here, we are looking at reactions with two methyl propene in basically all acidic environments.
00:10
So if we start off with hbr, but the basic common intermediate that they're all going to form is this tertiary carbokadion.
00:19
Once the, basically this alkyne picks up a proton.
00:24
So we're always working in acidic environments.
00:27
So then what we then form, as the first product then, would be bromine output position.
00:38
So two bromotumethyl propane.
00:43
Okay.
00:44
Then, if we were to have hcl, it would be a very similar thing.
00:49
First, we would protonate, form this tertiary -stable carbonation.
00:54
The chloride would come in and basically nucleophilic attack that site.
00:58
To now form two chloro, two methyl, propane.
01:06
Okay, the next one was water.
01:12
So same thing...