00:03
Let's try to predict the product of various alkene reactions.
00:07
Well, we're only going to be reacting hbr, but let's see what happens if we react it with different alkenes.
00:15
Well, for the first one, we know that there will be a most substituted halogen.
00:27
The halogen will always try to go to the most substituted carbon or the most substituted position.
00:33
And we also know that there's going to be carbocations.
00:38
So the hydrogen will be right here, and it'll take those electrons from the double bond.
00:48
The double bond will give those hydrogens to the, or give the electrons to the hydrogen, and the hydrogen will give the electrons to the bromine, leading us to a carbocation and a bromine with a negative charge.
01:09
And this will be true for every other problem.
01:15
And the bromine will then bond to this carbon because what we have is this intermediate with a carbocadion.
01:23
Right? you know, this intermediate and a bromine negative, the bromine is just going to give the electrons to that carbon.
01:34
And since it's already the most substituted carbocadion, there is no additional intermediate step.
01:43
For this one, same thing.
01:46
Electrons are donated to the hydrogen, hydrogen gives it to the bromine, and we end up getting this carbocadion.
01:57
It's already the most stable one.
01:59
Therefore, we end up with this product...