00:03
Let's predict some products of different alkene reactions.
00:07
So for the first one, if we reacted this alkeen with hcl, we would end up getting a cl substitute in the most substituted carbon that it can be placed in, which will be that one.
00:28
In the next reaction, we have br2 with ch30h, which is methanol.
00:35
For this one, because of oxygen being more nucleophilic, this will take the most substituted carbon, and we will get br here.
00:49
This is a peroxycarboxylic acid, and we know that this creates epochsides.
00:56
So we'll end up with this product.
01:02
Here we have h2s -a -4 with h2o.
01:06
We know that this will just give us an alcohol group in the most substituted.
01:12
Positioned nearby the alkyne.
01:18
Cl2 and h2o is very similar to the bromine and alcohol problem, except in this case, instead of an alcohol, we're using water, and we're creating an alcohol.
01:34
And instead of bromine, we have cl.
01:39
Here, this will be an ozenolysis, so this will cleave this bond, the alkyne like that, and on both.
01:50
Sides there would be a carbonyl group...