00:01
Okay, we have question 2 .19 and we have a glider moving through a photo gate.
00:11
And if you've ever used a photo gate, you know that it measures the time required, or the time that like a beam is blocked.
00:23
It uses that and the length of the object to figure out velocity, right? so they give us, as i say, that the average velocity vd of the glider is the length of the glider divided by the time it takes for the glider to pass through the gate or the time the beam in the photo gate is blocked, right? that's delta td.
00:52
So we suppose that acceleration is constant.
01:01
And then we want to think about is vd.
01:06
Equal to the instantaneous velocity of the glider when it's halfway through the photo gate in space.
01:13
So halfway through the photo gate in space means we'll do kind of like a top -down view.
01:20
Here's the photo gate, do the glider in red.
01:23
Here's your glider.
01:27
This is kind of a top -down view, right? our glider is moving, let's say it's moving to the right.
01:40
So it's halfway through the photo gate in space, meaning its length, if you found half of its length, half of its length would be right at the center of the photo gain.
01:54
So is vd equal to the instantaneous velocity of the glider at this point in space? the answer is no, because the acceleration, acceleration means the velocity, changes uniformly in time.
02:41
And specifically constant acceleration means this...