Question
A heat engine works in a cycle between reservoirs at $273 \mathrm{~K}$ and $490 \mathrm{~K}$. In each cycle, the engine absorbs $1250 \mathrm{~J}$ of heat from the high-temperature reservoir and does $475 \mathrm{~J}$ of work. (a) What is its efficiency? (b) By how much is the entropy of the universe changed when the engine goes through one full cycle? (c) How much energy becomes unavailable for doing work when the engine goes through one full cycle?
Step 1
Substituting the given values, we get: \[ \eta = \frac{475 \, \text{J}}{1250 \, \text{J}} = 0.38 \] So, the efficiency of the engine is \(38\%\). Show more…
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A heat engine works in a cycle between reservoirs at 273 and $490 \mathrm{~K}$. In each cycle the engine absorbs $1250 \mathrm{~J}$ of heat from the high-temperature reservoir and does $475 \mathrm{~J}$ of work. (a) What is its efficiency? (b) What is the change in entropy of the universe when the engine goes through one complete cycle? (c) How much energy becomes unavailable for doing work when the engine goes through one complete cycle?
A heat engine works in a cycle between reservoirs at 273K and 490K. In each cycle, the engine absorbs 1250 J of heat from the high-temperature reservoir and does 475 J of work. a) What is its efficiency? b) What is the change in entropy of the universe when the engine goes through one complete cycle? c) How much energy becomes unavailable for doing work when the engine goes through one complete cycle?
A Carnot engine is operated between two heat reservoirs at temperatures of 520 $K$ and 300 $K$. (a) If the engine receives 6.45 $kJ$ of heat energy from the reservoir at 520 $K$ in each cycle, how many joules per cycle does it discard to the reservoir at 300 $K$? (b) How much mechanical work is performed by the engine during each cycle? (c) What is the thermal efficiency of the engine?
The Second Law of Thermodynamics
The Carnot Cycle
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