00:01
Okay, so we have a hiker on a bridge that is one -fifth of the way to the, one -fifth of the way across the bridge.
00:09
I'll call the bridge length l.
00:11
So this is 985 meters here.
00:14
And the bridge itself weighs 3 ,610.
00:19
Right? since it's even, we can say that it is just halfway.
00:25
Now we have two supports.
00:28
We'll say n1 and n2 here.
00:30
So i so.
00:31
Now to find n1, the force on the near end, we're going to consider the axis of rotation on the far end here.
00:42
So the sum of the torques is going to be equal to zero since the system is in equilibrium.
00:49
So we're going to have the sum of all the torques.
00:52
So we have the first torque here is going to be, or we'll call this the first torque here, 3 ,610 newtons times one half of l plus.
01:11
So we're going to consider this is the positive direction.
01:15
And then 985 here, 985 newtons times, and then that's 4 fifths other way, so 4 fifths l...