Question
(a) How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere $30.0 \mathrm{~cm}$ in diameter to produce an electric field of $1150 \mathrm{~N} / \mathrm{C}$ just outside the surface of the sphere? (b) What is the electric field at a point $10.0 \mathrm{~cm}$ outside the surface of the sphere?
Step 1
The diameter of the sphere is given as \(30.0 \, \text{cm}\). Therefore, the radius \(r\) is half of the diameter: \[ r = \frac{30.0 \, \text{cm}}{2} = 15.0 \, \text{cm} = 0.15 \, \text{m} \] Show more…
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$\bullet$(a) How many excess elec- trons must be distributed uni- formly within the volume of an isolated plastic sphere 30.0 $\mathrm{cm}$ in diameter to produce an elec- tric field of 1150 $\mathrm{N} / \mathrm{C}$ just out- side the surface of the sphere? (b) What is the electric field at a point 10.0 cm outside the surface of the sphere?
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