00:01
Okay, in this problem, we are given electrons and protons with wavelength of 0 .06 nanometers, and we're asked to find for both what voltage would be required to accelerate these particles up to a speed in which their wavelength is equal 0 .06 nanometers.
00:19
So the equations we'll need.
00:21
We'll need the definition of a de brogley wavelength, which is the plank constant h over the momentum of the particle.
00:27
We need to remember the definition of momentum, p equals mv, of course.
00:31
And for the case of particles being accelerated through a potential difference, we can note that the particle starts from rest.
00:40
And so its kinetic energy will be equal to the potential energy gained through this potential difference, which is simply the charge e times the voltage, the delta v.
00:53
Note this is not electron volts.
00:54
This is the electron charge times the voltage.
00:57
And the reason we're using e for the electron charge is because it works for both electrons and protons.
01:04
They have the same charge.
01:06
Okay, so let's jump into it.
01:09
So to start off, we can say lambda equals h over p, which is equivalent to h over mv.
01:21
So we need to find a velocity of these particles being accelerated through a potential difference...