00:01
Okay, so we've got a ball being dropped from 5 .2 meters above water.
00:09
So y sub 0 is 5 .2 meters.
00:16
Okay.
00:17
So v is going to equal v0 minus gt, but i don't want to use that.
00:27
I want to use v squared equals v0 squared, which is zero, plus 2gy0.
00:48
So v is going to be the square root of 2gy0.
00:54
Okay.
00:56
So we know that y0 is 5 .2, g is 9 .81, the square.
01:06
Root v equals square root of 2g y 0.
01:16
So that's going to be 10 meters per second.
01:24
All right.
01:29
It reaches the bottom of the lake four seconds after it's dropped, but it's on a constant velocity in the lake.
01:36
So v is a distance over time.
01:42
If time is 4 .8 seconds, then distance would be vt.
01:54
So that's 10 times 4 .8.
01:58
I'm going to write in t equals 4 .8.
02:04
B equals vt.
02:06
So that gives me 48.
02:13
Yep, 48 meters.
02:22
Okay.
02:22
Okay, b, b, b, b, b, b, b, b, b, b, b, b, b, b, b, b...