00:01
In this exercise, we have a light emitting diode or a lead that works by exciting an electron to the conduction band, and then when the electron falls back to the valence band, it emits a photon.
00:14
The bend gap of the lead is 2 .86 electron volts.
00:20
This is the difference between the two, the conduction band and the valence band.
00:26
And in question a, we have to find what is the wave loss? length of the emitted light.
00:34
Notice that the energy of the photon that's emitted is just the band gap, because it's the difference between the energies of the two bands, the conduction band, and the valence band.
00:49
And we also know how to write the energy of the photon as a function of the wavelength lambda.
01:03
So what we're going to do is to write it, e equals hc over lambda, so lambda is equal to hc over e.
01:15
Hc is 1 ,240 electron volts nanometers, while e is 2 .86 electron volts, so lambda is equal to 525 .4 nanometers...