Given that the feed is 50.0 mole $\%$ benzene, the molar flow rate of benzene ($F_{B}$) is $0.50 \times 1320 = 660 \, \text{mol/s}$. The balance is toluene, so the molar flow rate of toluene ($F_{T}$) is $1320 - 660 = 660 \, \text{mol/s}$.
Show more…