00:01
In this question, we will be using these two properties of logarithms to simplify some logarithmic expressions.
00:12
First, we have long seek plus long coase, longs of theta, plus lawn of cost of theta.
00:20
Since we have a cos here and a secant has to do with coes, let's rewrite it in terms of cost.
00:27
That is, let's write secant as 1 over cos, 1 over cosine.
00:37
And since 1 over cosine is cosine to the negative 1, this first term would be negative long of cosup theta, which when added to the other term results in 0.
01:01
Our second expression is lon of 8x minus 4, minus 2, lawn of 2.
01:08
Since we have a lot of 2 and we might be able to cancel it out, like it was, like it was, in the first question, as well as the case in the first question, let's try to have, let's try to find a lawn two inside of here.
01:26
Simplify it so that we get a lawn two somewhere.
01:30
I'll notice we could use, we could factor this and then use the property that allows us to split products.
01:41
We could factor 8x plus 4 into 4 times 2x plus 1 and then split this logarithm up into two different ones...