The derivative of the function $f(x)=\frac{x^{2}}{x^{2}-1}$ is given by:
$$f'(x)=\frac{2x(x^{2}-1)-2x^{3}}{(x^{2}-1)^{2}}=\frac{-2x}{(x^{2}-1)^{2}}$$
Setting this equal to zero gives us $x=0$ as a critical point. The function is also undefined at $x=\pm1$, so
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