00:01
Consider the following figure where the wire cd is free to slide up vertically.
00:07
Both cd and ab carry a current of i.
00:10
We know that for two parallel conductors carrying current in the same direction attract each other and for two parallel conductors carrying current in opposite directions ripple each other.
00:23
Since the current in the two wires flow in the opposite direction, then the two wires repel each other.
00:31
We need to find the equilibrium height edge with the wire cd rise.
00:38
Let's f1 be the magnetic force between the wires.
00:42
Then the wire cd rises until the upward force f1 due to the currents balances the downward force of gravity mg so that i can write f1 minus m g is equal to zero let's say equation number one the magnitude of the force per unit land between two wires carrying current of i and i -dash is given by f -i -l is equal to mu -0 i -dash -i upon 2 pi r.
01:28
So we will have f -dash -i or you can say that instead of f -i, sorry, not f -dish -i, it's a f -i.
01:41
Or f i is equal to also m g f is equal to m g that we know newton second law is equal to mu zero i dash i into l upon two pi r because this l will go here but we know that i dash is equal to i so let me write i dash is equal to i and r is equal to edge so we can rewrite this formula and we can write it in the form of edge also...