00:01
Consider the case of a part on a machine rotating at an initial angular velocity of 0 .06 radiance per second.
00:09
We have omega -i for the initial angular velocity is 0 .060 radians per second.
00:19
This part experiences an angular acceleration alpha of 0 .70 radians per second squared, while it reaches its final velocity, omega f, of 2 .2 radians per second.
00:38
We are interested in finding out what angle the heart rotates through while it's going from its initial angular velocity to its final angular velocity.
00:49
And this will be delta theta.
00:54
We begin by writing down one of our equations for the rotational motion of a rigid object.
01:01
We have the final angular velocity.
01:03
Squared equals the initial angular velocity squared plus two times the angular acceleration times delta theta which is the change in the initial and final angles because we're interested in delta theta we'll rearrange this so that delta theta is on the left and everything else is on the right so we have delta theta equals the difference between the final angular velocity squared and the initial angular velocity squared, all over two times alpha the angular acceleration.
01:40
We already know that the final angular velocity is 2 .2 radiance per second.
01:46
So we have that.
01:47
We know that the initial angular velocity is 0 .06 radiance per second.
01:53
So we have that.
01:54
And we also know that the angular acceleration is 0 .7 radians per second squared.
02:00
And we also have that.
02:01
Therefore, we have everything we need to be able to solve for delta theta.
02:08
So we can plug these values in.
02:11
For omega f, we have 2 .2 radians per second, close the parentheses and square it, minus 0 .060 radians per second, close the parentheses and square that...