00:01
In this exercise, we have a doubly ionized magnesium atom that has a mass, an atomic mass of 24, and that is accelerated by a potential difference of 22 kilo -volt.
00:14
And we want to calculate what is the doubly wavelength of this atom.
00:21
So what i'm going to do, first of all, is to calculate the kinetic energy of the magnesium atom after it's accelerated.
00:29
And from the kinetic energy, i can calculate the momentum, and from the momentum, we can calculate the dabburly wavelength.
00:39
So first of all, notice that since the magnesium atom is doubly ionized, the charge q of the magnesium atom is plus two times a charge of the electron.
00:52
Okay? okay.
00:54
And we know that the kinetic energy of an accelerated charge is the charge times the potential difference delta v.
01:04
So in our case, the charge is 2e and delta v is 22 times 10 to the third volt.
01:17
So what we have is that e is equal to 1 .6 times 6...