Question
A man is moving on his bike with $54 \mathrm{kmh}^{-1}$. He takes a u-turn in $10 \mathrm{~s}$ and continues to move with the some velocity. Find average acceleration during this time.(A) $3.0 \mathrm{~ms}^{-2}$(B) $1.5 \mathrm{~ms}^{-2}$(C) 0(D) $-1.5 \mathrm{~ms}^{-2}$
Step 1
We can convert this into meters per second by multiplying by $\frac{5}{18}$. So, $v_1 = 54 \times \frac{5}{18} = 15 \mathrm{ms}^{-1}$. We can write this in vector form as $v_1 = +15 \hat{i}$. Show more…
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