A man starts from O moves 500 m turns by 60^∘ and moves 500 m again turns by 60^∘ and moves 50

Name: Problem 86, Chapter 1: A Complete Resource Book in Physics for JEE Main
Uploaded: 2021-10-10T00:19:09-08:00
Duration: 4 min 10 s
Channel: Akshaya Rs
Description: A man starts from O moves 500 m turns by 60^∘ and moves 500 m again turns by 60^∘ and moves 500 m and so on. Find the displacement after (i) 5 th turn, (ii) 3 rd turn (A) 500 m, 1000 m (B) 500 m, 500 √(3) m (C) 1000 m, 500 √(3) m (D) None of these

step 1 In this question we will learn about some basic concept of the vectors. The question is a man st

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A man starts from $O$ moves $500 \mathrm{~m}$ turns by $60^{\circ}$ and moves $500 \mathrm{~m}$ again turns by $60^{\circ}$ and moves $500 \mathrm{~m}$ and so on. Find the displacement after (i) 5 th turn, (ii) 3 rd turn (A) $500 \mathrm{~m}, 1000 \mathrm{~m}$ (B) $500 \mathrm{~m}, 500 \sqrt{3} \mathrm{~m}$ (C) $1000 \mathrm{~m}, 500 \sqrt{3} \mathrm{~m}$ (D) None of these

   A man starts from $O$ moves $500 \mathrm{~m}$ turns by $60^{\circ}$ and moves $500 \mathrm{~m}$ again turns by $60^{\circ}$ and moves $500 \mathrm{~m}$ and so on. Find the displacement after (i) 5 th turn, (ii) 3 rd turn
(A) $500 \mathrm{~m}, 1000 \mathrm{~m}$
(B) $500 \mathrm{~m}, 500 \sqrt{3} \mathrm{~m}$
(C) $1000 \mathrm{~m}, 500 \sqrt{3} \mathrm{~m}$
(D) None of these

A Complete Resource Book in Physics for JEE Main

Sanjeev Kumar 1st Edition

Chapter 1, Problem 86

Instant Answer

Solved by Expert Akshaya Rs

10/10/2021

Step 1

After the first turn of 60 degrees, he moves another 500 m to point B. After the second turn of 60 degrees, he moves another 500 m to point C. This pattern continues. Show more…

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A man starts from $O$ moves $500 \mathrm{~m}$ turns by $60^{\circ}$ and moves $500 \mathrm{~m}$ again turns by $60^{\circ}$ and moves $500 \mathrm{~m}$ and so on. Find the displacement after (i) 5 th turn, (ii) 3 rd turn (A) $500 \mathrm{~m}, 1000 \mathrm{~m}$ (B) $500 \mathrm{~m}, 500 \sqrt{3} \mathrm{~m}$ (C) $1000 \mathrm{~m}, 500 \sqrt{3} \mathrm{~m}$ (D) None of these

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Key Concepts

Vector Addition

This concept involves summing multiple displacement vectors to determine the net displacement. In the context of planar motion, each step has both magnitude and direction, and the overall displacement is found by adding these vector components, which is central to solving problems involving non-linear paths.

Rotational Transformations

Each change in the traveler’s direction corresponds to a rotation of the initial vector by a fixed angle. Understanding how rotations alter the direction of vectors is crucial for correctly decomposing and summing the individual movement vectors.

Polygonal Paths

When equal-length displacements are connected by constant angular turns, they often form polygonal or near circular paths. Recognizing this pattern helps in applying geometric reasoning and symmetry properties to calculate the resulting displacement efficiently.

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