Question
A metal rod is 40.125 $\mathrm{cm}$ long at $20.0^{\circ} \mathrm{C}$ and 40.148 $\mathrm{cm}$ long at $45.0^{\circ} \mathrm{C}$ . Calculate the average coefficient of linear expansion of the rod for this temperature range.
Step 1
The initial length of the rod, $L_0$, is 40.125 cm. The initial temperature, $T_0$, is 20.0°C. The final length of the rod, $L$, is 40.148 cm. The final temperature, $T$, is 45.0°C. Show more…
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$\cdot$ A metal rod is 40.125 $\mathrm{cm}$ long at $20.0^{\circ} \mathrm{C}$ and 40.148 $\mathrm{cm}$ long at $45.0^{\circ} \mathrm{C} .$ Calculate the average coefficient of linear expansion of the rod's material for this temperature range.
A metal rod is $40.125 \mathrm{~cm}$ long at $20.0^{\circ} \mathrm{C}$ and $40.148 \mathrm{~cm}$ long at $45.0^{\circ} \mathrm{C}$. Calculate the average coefficient of linear expansion of the rod's material for this temperature range.
A metal rod is 40.125 m long at 20°C and 40.148 m long at 45°C. Calculate the average linear expansion coefficient in this temperature range.
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