00:01
This question reads, a missile's trajectory takes it to a maximum altitude of 12 ,000 kilometers.
00:16
So the altitude is interesting.
00:21
Notice that that's a maximum altitude.
00:25
12, not 12 ,000, 1 ,200 kilometers.
00:33
So that would be 1 ,200 ,000 meters.
00:38
Notice that it says that it's maximum altitude.
00:40
That means that its velocity when it reaches that altitude.
00:45
So i'm going to write v.
00:47
Sub final is zero.
00:51
It's launch speeds.
00:53
That's v initial.
00:56
Is 6 ,100 meters per second.
01:04
And again, it goes to 1 ,200 kilometers, which is 1 ,200 ,000 meters.
01:10
How fast is it moving at the peak of its trajectory? okay, so perhaps that's telling us that the peak of its trajectory is not zero.
01:32
So we'll put a question mark there.
01:35
Okay.
01:37
So we can write kinetic energy initial plus potential energy initial equals kinetic energy final, plus potential energy final.
01:54
So one half m v initial.
02:01
Okay, we do have the initial.
02:03
So i'm going to write v.
02:09
Minus g m little m over our initial well the initial radius is the radius of the earth the initial distance is the radius of the earth because it starts from earth equals k final one half m v squared so that's what we're trying to figure out i'm going to put a sub f there even though it's a little bit hard to write on this whiteboard um and then minus g m, little m, over r final.
02:49
Well, our final, we're given an altitude, so this would have to be the radius of the earth plus the altitude.
02:58
Okay, so we just need to solve for v final.
03:03
So first thing that i'm going to do is i'm going to add this term to both sides.
03:08
So that's going to give me one -half m v .i squared plus.
03:18
I'm also going to factor out the gm -m -1 over r -sub -e plus h minus 1 over r -sub -e.
03:41
And that equals 1 -half m v.
03:49
Squared...