00:01
So in this problem, we're given a reaction.
00:03
It's a gorychometric reaction between elemental sulfur and chlorine gas to form disulfur di -chloride and sulfur dichloride.
00:13
Now, this is actually a two -step reaction, which i've represented as two steps here.
00:18
So first, disulfuride chloride is formed, and then any excess chlorine reacts with disulfur di -chloride to form sulfur dioxide.
00:26
So our first step is to figure out how much disulfur di -chloride is formed in the first.
00:30
Step and then we'll figure out how much is used to form sulfur dichloride in the second step, considering that our final answer of interest is the amount of disulfur dichloride that is formed.
00:40
So we'll start by converting everything to moles.
00:43
We have 50 grams of sulfur over its molecular weight, 256 .52 gives us 0 .195 moles of sulfur.
01:00
That's a terrible eight.
01:01
Let's try that again.
01:02
There we go.
01:04
And we have 102 grams of chlorine, to 102 grams of chlorine over its molecular weight.
01:14
C .69 .94 gives us 1 .458 moles of chlorine...