00:01
For this exercise, we have a muon and an anti -mewan that are annihilated and produce two photons.
00:11
And these two particles, the muon and the antimium, are initially at rest.
00:18
And we're given the information that the mass of the muam is given by 207 times the mass of the electron.
00:26
And since the mass of the electron, i'm going to write it up here, the mass of the electron is given by 0 .0 .5 .5 .5.
00:32
0 .51 mega electron volts per c squared.
00:39
We're gonna have the mass of the muum as 207 times 0 .51, which is 105 .57 megachron volts per c squared.
00:56
Okay? and given these informations, we are asked to calculate what is the wavelength of the photons given that the wavelength of the two photons are the same.
01:11
So the first thing we need to calculate is what is the energy of the system initially.
01:19
That is to calculate the rest energy of the muons.
01:24
So the rest energy of the muons is going to be 2m -mue c squared...