00:01
In this question we have white light shining on silicate flints glass.
00:05
We want to find out the angle delta data between the 400 nanometer and 700 nanometer dispersed.
00:15
So this is about dispersion, okay, and we know that the refractive index changes with the wavelength of the visible light.
00:25
So from the graph, okay, we found that at, lambda equals to 400 nanometers, the refractive index is 1 .66, and then at lambda equals to 700 nanometer, then refractive index is 1 .6.
00:45
Okay, so this is from figure to 3 .17.
00:53
So to find, so we have a refraction taking place.
00:59
So we need to label the angle of so the here is 55 degrees and we have 35 degrees over here.
01:10
Okay.
01:12
So the angle or refraction for each one, okay, it will be labeled here.
01:26
This is the data r.
01:28
So the delta data is the is the refractive angle, angle of reflection of red light minus the angle of reflection of blue light.
01:44
Okay.
01:46
Okay.
01:47
So for lambda or wireless light, okay, not blue, but violet.
01:57
Okay, so for lambda it goes to 400 nanometers, okay, and then we calculate the n is 1 .66 then using snal's law, now gives us, side, okay, so the refractive index of air times side 35 degrees equals to 1 .66, side data are pilot.
02:31
Okay, so just to mention snell's law, here we have n1, sine data 1 equals 2, and 2, side data 2...