Question
A NOT gate is modeled using an inverter similar to that shown in Figure P11.20. For $V_{\text {in }}=V_{D D}=5 \mathrm{~V}$ and $V_{\text {out }}=0.2 \mathrm{~V}$, determine the load resistance, $R_L$, and the $n$-channel ON source-to-drain resistance $\left(r_{o n}\right)$ if the power dissipated in the load resistance during $\mathrm{ON}$ state is $0.48 \mathrm{~mW}$.
Step 1
We have: - \( V_{in} = V_{DD} = 5 \, \text{V} \) - \( V_{out} = 0.2 \, \text{V} \) - Power dissipated in the load resistance, \( P = 0.48 \, \text{mW} = 0.48 \times 10^{-3} \, \text{W} \) Show more…
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