00:01
In the first part of this question, we're going to be drawing the structures of pt, cl4, with an overall charge of negative 2, and pt, nh3, 4 with an overall charge of positive 2.
00:15
So we've got pt surrounded by 4 chlorine or chloride ligands with an overall charge of 2 negative, and we've got p .t also surrounded by n .h3 ligands.
00:34
With an overall charge of positive 2.
00:38
Now the substitution of 2 moles of ammonia group into this complex right here for the formation of cispt, cl to nh2, nh3, it gives us pt, cl, cl, cl, cl, cl, cl, cl, cl, cl, cl, the nh3 by removing the first chloride would have pt, nh3, cl, cl, and then removing or substituting another chloride with an nh3 would have a pt, nh3, nh3, cl, cl, and this is the cis form that we are looking at.
01:39
Substituting of two moles of chloride group.
01:44
We are looking at an initial pt, nh3, nh3, nh3, nh3...