00:01
In this question, we have a parallel plate capacitor that is initially in air.
00:07
It has a plate separation d of 1 .5 cm, plate area, 25 cm square, and then it's charged to 250 volts.
00:24
And then after it's charged to 250 volts, it's disconnected from the source, then in water.
00:31
So we want to find the charge on the plates before in the place.
00:34
After the immersion, the capacitance and voltage of the immersion and the change in energy of the capacitor.
00:42
So to do part a, the charge on the plates before and after immersion.
00:51
So one thing we need to know is that since the plates are disconnected after charge to 250 volts.
01:11
So q before equals to q after.
01:23
Because it's already disconnected before immersion.
01:36
Right? so the q will be q before and q after will just be q before.
01:46
And q before is c times v or c knot times v.
01:51
C not is epsilon knot a over d.
01:53
Then multiply by b and then you put in the numbers k d is 1 .5 cm so 1 .5 times 10 to the 0 .m and b is 150 and the answer is 3 .69 times 10 to the power negative 10 columns okay so this is the answer for part a okay then in part b need to calculate the capacitance and voltage after immersion.
02:39
So using c prime it goes to kappa c knot...