A parallel-plate capacitor is constructed by filling the space between two square plates with blocks of three dielectric materials, as in Figure $\mathrm{P} 26.61 .$ You may assume that $\ell \gg d$. (a) Find an expression for the capacitance of the device in terms of the plate area $A$ and $d, \kappa_{1}, \kappa_{2},$ and \kappa $_{3}$. (b) Calculate the capacitance using the values $A=1.00 \mathrm{cm}^{2}, \quad d=2.00 \mathrm{mm}, \quad \kappa_{1}=4.90, \quad \kappa_{2}=5.60,$ and $\kappa_{3}=2.10$.
CAN'T COPY THE FIGURE