Question

Q2. A parallel-plate capacitor is constructed by filling the space between two square plates with blocks of three dielectric materials, as in Figure You may assume that $l >> d$ a) Find an expression for the capacitance of the device in terms of the plate area $A$ and $d, kappa_1, kappa_2$ and $kappa_3$. b) Calculate the capacitance using the values $A = 3cm^2, d = 1.5mm, kappa_1 = 6, kappa_2 = 3, kappa_3 = 5$ and $Delta V = 16V$.

          Q2. A parallel-plate capacitor is constructed by filling the space between two square plates with blocks of three dielectric materials, as in Figure You may assume that $l >> d$
a) Find an expression for the capacitance of the device in terms of the plate area $A$ and $d, kappa_1, kappa_2$ and $kappa_3$.
b) Calculate the capacitance using the values $A = 3cm^2, d = 1.5mm, kappa_1 = 6, kappa_2 = 3, kappa_3 = 5$ and $Delta V = 16V$.

Q2. A parallel-plate capacitor is constructed by filling the space between two square plates with blocks of three dielectric materials, as in Figure You may assume that l >> d
a) Find an expression for the capacitance of the device in terms of the plate area A and d, kappa1, kappa2 and kappa3.
b) Calculate the capacitance using the values A = 3cm^2, d = 1.5mm, kappa1 = 6, kappa2 = 3, kappa3 = 5 and Delta V = 16V.

Added by Sandra C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

06/16/2022

Step 1

Step 1: Represent the capacitor as three regions in parallel (areas add) with plate separation d; each region has capacitance Ci = (κi ε0 Ai)/d. Show more…

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Q2. A parallel-plate capacitor is constructed by filling the space between two square plates with blocks of three dielectric materials, as shown in Figure 1. You may assume that (d >> a). Find an expression for the capacitance of the device in terms of the plate area A and d, ̄1, ̄2, and ̄3. b) Calculate the capacitance using the values A = 3 cm^2, d = 0.5 mm, ̄1 = 6.4, ̄2 = 3.4, and ̄3 = 5.