Question
A parallel plate capacitor is constructed from two square conducting plates of length $L=0.10 \mathrm{m}$ on a side. There is air between the plates, which are separated by a distance $d=89 \mu \mathrm{m} .$ The capacitor is connected to a $10.0-\mathrm{V}$ battery. (a) After the capacitor is fully charged, what is the charge on the upper plate?(b) The battery is disconnected from the plates and the capacitor is discharged through a resistor $R=0.100 \mathrm{M} \Omega .$ Sketch the current through the resistor as a function of time $t(t=0$ corresponds to the time when $R$ is connected to the capacitor). (c) How much energy is dissipated in $R$ over the whole discharging process?
Step 1
The capacitance of a parallel plate capacitor is given by $C = \varepsilon_0 \frac{A}{d}$, where $\varepsilon_0$ is the permittivity of free space, $A$ is the area of one of the plates, and $d$ is the separation between the plates. Show more…
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