A parallel-plate capacitor with plate separation $d$ has the space between the plates filled with two slabs of dielectric, one with constant $K_{1}$ and the other with constant $K_{2, \text { and each }}$ having thickness $d / 2$ . (a) Show that the capacitance is given by $C=\frac{2 \epsilon_{o} A}{d}\left(\frac{K_{1} K_{2}}{K_{1}+K_{2}}\right) \cdot($Hint: Can you think of this combination as two capacitors in series? (b) To see if your answer is reasonable, check it in the following cases: (i) There is only one dielectric, with constant $K,$ and it completely fills the space between the plates. (ii) The plates have nothing but air, which we can treat as vacuum, between them.