0:00
In this problem.
00:01
Ah, the curved crank.
00:05
His inflate lind l physical to zero point for meters and height, etch is equal to, uh, 0.2 meters on the coefficient of kinetic friction.
00:27
Um, you okay? mu k is equal to ah, zero point two.
00:38
The particle is released from rested point here on dde.
00:43
It moves through a curved crack.
00:47
Well, let us apply the conservation of energy according to conservation, according to conservation oh, energy.
01:02
We have, uh, kinetic energy at point a unless potential energy at point a so some of kinetic energy, it points a and potential energy point a equals kinetic energy.
01:25
Ah, where the particle stops and looks said, it's, uh okay, hole plus you or bless the heat energy.
01:41
Um, thermal.
01:47
But k is the kinetic energy in the it point a you is a potential energy.
01:55
Good point.
01:57
Where is, uh, be terminal? is the thermal energy from the kinetic friction? all right, so we have mm g h plus.
02:12
Zito is equal to zero place m g capital.
02:19
H bless.
02:24
Um uk times are times capital l all right.
02:31
So here capital, which is the height where the particle stops so, captain, which is the height of the particle stops, and our is the normal force applied on the particle, and, uh, it's equal are to the weight off the particle.
02:50
Um, so we have by putting the values we have 9.8 multiply by 0.2 is equal to mine.
03:03
0.8 multiplied by capital itch.
03:09
Unless, um, is it a point to multiply by? um, my point...