Question
A particle moves along the $x$ axis according to the equation $x=2.00+3.00 t-t^{2}$, where $x$ is in meters and $t$ is in seconds. At $t=3.00 \mathrm{~s}$, find (a) the position of the particle, (b) its velocity, and (c) its acceleration.
Step 1
00+3.00 t-t^{2}$. We need to find the position at $t=3.00 \mathrm{~s}$. We substitute $t=3.00$ into the equation to find the position. Show more…
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A particle moves along the $x$ axis according to the equation $x=2.00+3.00 t-$ $1.00 t^{2},$ where $x$ is in meters and $t$ is in seconds. At $t=3.00 \mathrm{s},$ find $(\mathrm{a})$ the position of the particle, $(\mathrm{b})$ its velocity, and (c) its acceleration.
A particle moves along the $x$ axis according to the equation $x=2.00+3.00 t-1.00 t^{2},$ where $x$ is in meters and $t$ is in seconds. At $t=3.00 \mathrm{s},$ find (a) the position of the particle, (b) its velocity, and (c) its acceleration.
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