Question
A particle moves along the $x$ axis according to the equation $x=2.00+3.00 t-1.00 t^{2},$ where $x$ is in meters and $t$ is in seconds. At $t=3.00 \mathrm{s},$ find (a) the position of the particle, (b) its velocity, and (c) its acceleration.
Step 1
The position of the particle as a function of time is given by the equation: \[ x(t) = 2.00 + 3.00t - 1.00t^2 \] Show more…
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A particle moves along the $x$ axis according to the equation $x=2.00+3.00 t-t^{2}$, where $x$ is in meters and $t$ is in seconds. At $t=3.00 \mathrm{~s}$, find (a) the position of the particle, (b) its velocity, and (c) its acceleration.
A particle moves along the x-axis according to the equation x = 2.00 + 3.00 t - 1.00 t², where x is in meters and t is in seconds. At t = 3.00 s, find (a) the position of the particle, (b) its velocity and (c) its acceleration.
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