00:01
Question 67, we are looking at a velocity function, v of t, equals 1 over the square root of t, which means the velocity is a prime, so it's already a v prime.
00:21
To get to our position function, we would have to take the integral.
00:26
So we're going to call that x of t, and that is really a v prime.
00:42
T to the negative 1 half power d t.
00:50
So when i integrate that, when i take the integral, i'm going to get t, i add one.
01:00
So it's going to be a positive 1 half.
01:02
And i multiply the coefficient by the reciprocal of the exponent.
01:09
2 plus c.
01:12
So x of t equals two, t is the one half, which is a square root of t plus c.
01:26
And to find c, we're going to use the fact that we know the position is four when x is one...