Question
A particle moves in the $x-y$ plane under the action of force $\vec{F}$ such that the value of its linear momentum 2 at any instant is $p=2(\cos t \hat{i}+\sin t \hat{j})$. The angle $\theta$between $F$ and $p$ is(A) $60^{\circ}$(B) $45^{\circ}$(C) $30^{\circ}$(D) $90^{\circ}$
Step 1
We know that force $\vec{F}$ is given by the rate of change of momentum, i.e., $\vec{F} = \frac{d\vec{p}}{dt}$. Show more…
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A particle moves in the $x-y$ plane under the action of force $\vec{F}$ such that the value of its linear momentum $\vec{P}$ at time $t$ is $P_{x}=2 \cos t$ and $P_{y}=2 \sin t .$ The angle $\theta$ between $\vec{F}$ and $\vec{P}$ at time $t$ will be (A) $90^{\circ}$ (B) $0^{\circ}$ (C) $180^{\circ}$ (D) $30^{\circ}$
A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t are p x = 2 cos t, p y= 2 sint . The angle between F and p at time t is (a) 90° (b) 0° (c) 180° (d) 30°
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