Question
A particle of mass $2 \mathrm{~kg}$ starts moving in a straight line with an initial velocity of $2 \mathrm{~ms}^{-1}$ at a constant acceleration of $2 \mathrm{~ms}^{-2}$. Then rate of change of kinetic energy(a) is four times the velocity at any moment(b) is two times the displacement at any moment(c) is four times the rate of change of velocity at any moment(d) is constant through out
Step 1
Step 1: The rate of change of kinetic energy is given by the formula $\frac{dK}{dt} = m \cdot a \cdot v$, where $m$ is the mass of the particle, $a$ is the acceleration, and $v$ is the velocity. Show more…
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A particle of mass $2 \mathrm{~kg}$ starts moving in a straight line with an initial velocity of $2 \mathrm{~m} / \mathrm{s}$ at a constant acceleration of $2 \mathrm{~m} / \mathrm{s}^{2}$. The rate of change of kinetic energy is (A) Four times the velocity at any moment. (B) Two times the displacement at any moment. (C) Four times the rate of change of velocity at any moment. (D) Constant throughout.
A particle of mass $2 \mathrm{~kg}$ starts moving in a straight line with an initial velocity of $2 \mathrm{~m} / \mathrm{s}$ at a constant acceleration of $2 \mathrm{~m} / \mathrm{s}^{2}$. The rate of change of kinetic energy is (A) four times the velocity at any moment. (B) two times the displacement at any moment. (C) four times the rate of change of velocity at any moment. (D) constant throughout.
A particle of mass 2 kg starts moving in a straight line with an initial velocity of 2 m/s at a constant acceleration of 2 m/s2 . The rate of change of kinetic energy is
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