A particle of mass $m$ executes simple harmonic motion at angular frequency $\omega$. Initially it is in its ground state but from $t=0$ its motion is disturbed by a steady force $F .$ Show that at time $t>0$ and to first order in $F$ the state is
$$
|\psi, t\rangle=\mathrm{e}^{-\mathrm{i} E_{0} t / \hbar}|0\rangle+a_{1} \mathrm{e}^{-\mathrm{i} E_{1} t / \hbar}|1\rangle
$$
where
$$
a_{1}=\frac{\mathrm{i}}{\sqrt{2 m \hbar \omega}} \int_{0}^{t} \mathrm{~d} t^{\prime} F\left(t^{\prime}\right) \mathrm{e}^{\mathrm{i} \omega t^{\prime}}
$$
Calculate $\langle x\rangle(t)$ and show that your expression coincides with the classical solution
$$
x(t)=\int_{0}^{t} \mathrm{~d} t^{\prime} F\left(t^{\prime}\right) G\left(t-t^{\prime}\right)
$$
where the Green's function is $G\left(t-t^{\prime}\right)=\sin \left[\omega\left(t-t^{\prime}\right)\right] / m \omega .$ Show that a suitable displacement of the point to which the oscillator's spring is anchored could give rise to the perturbation.