Question
A particle of mass $m$ is subjected to a force acting in the $x$ -direction. $F_{x}=(3.00+0.500 x) \mathrm{N} .$ Find the work done by the force as the particle moves from $x=0.00$ to $x=4.00 \mathrm{~m}$
Step 1
In this case, the force is a function of position, $F_{x}=(3.00+0.500 x) \mathrm{N}$. So, we need to integrate this function from $x=0.00$ to $x=4.00 \mathrm{~m}$. Show more…
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