Question
A particle of mass $m$ is subjected to a force acting in the $x$ -direction. $F_{x}=(3.0+0.50 x) \mathrm{N}$. Find the work done by the force as the particle moves from $x=0$ to $x=4.0 \mathrm{~m}$
Step 1
In this case, the particle moves from $x=0$ to $x=4.0$ m. So, $\Delta x = 4.0 \, m - 0 = 4.0 \, m$. Show more…
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