A particle of rest energy $m c^{2}$ is moving with speed $v$ in the positive $x$ direction. The particle decays into two particles, each of rest energy $140 \mathrm{MeV}$. One particle, with kinetic energy $282 \mathrm{MeV},$ moves in the positive $x$ direction, and the other particle, with kinetic energy $25 \mathrm{MeV}$, moves in the negative $x$ direction. Find the rest energy of the original particle and its speed.