00:01
All right, the particle starts at the origin and has a velocity of 8 in the j direction meters per second.
00:17
And its acceleration is 4 in the i direction plus 2 in the j direction meters per second.
00:41
So i'm trying to figure out, i'm going to do time first, when the x coordinate is 29.
00:53
So x is going to equal x initial, which is zero, plus vx initial, which is 8 times t, plus one -half times the acceleration, which is 4 t squared.
01:13
So x needs to be 29.
01:19
So i'm going to rewrite this as 2t squared plus 8t minus 29 equals 0.
01:36
And now i'm just going to graph it and look for the y intercept.
01:40
2t squared plus 8t minus 29.
01:51
So i'm graphing it, and i see that the x intercept is at 2 .30 seconds.
02:07
So now i'm going to write t equals 2 .30 in my calculator.
02:14
Okay.
02:16
The question now is, in 2 .3 seconds, what is its y coordinate? it.
02:27
Well, y is going to equal y initial.
02:32
Oh, no, that eight, that eight was in the, in the y direction.
02:41
E, e, e, e, e, so x is going to equal vx, which was zero, plus one half a t squared.
02:55
Oh, man.
02:56
So that x again, that eight is again in the y direction.
03:08
So it's one half a t squared.
03:11
Okay, so now i just have to take the square root of 29 over two.
03:19
Man, t equals square root of 29 over two...