Question
A particle's acceleration along an $x$ axis is $a=5.0 t$, with $t$ in seconds and $a$ in meters per second squared. At $t=2.0 \mathrm{~s}$, its velocity is $+17 \mathrm{~m} / \mathrm{s}$. What is its velocity at $t=4.0 \mathrm{~s}$ ?
Step 1
0t$. We can find the velocity $v$ by integrating the acceleration with respect to time $t$. This gives us: \[v = \int a \, dt = \int 5.0t \, dt = 2.5t^2 + C\] where $C$ is the constant of integration. Show more…
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Additional Problems A particle's acceleration along an $x$ axis is $a=5.0 t,$ with $t$ in seconds and $a$ in meters per second squared. At $t=2.0 \mathrm{s}$ its velocity is $+17 \mathrm{m} / \mathrm{s}$ . What is its velocity at $t=4.0 \mathrm{s} ?$
A particle moves along the $x$ -axis according to the equation $x(t)=2.0-4.0 t^{2} \mathrm{m} .$ What are the velocity and acceleration at $t=2.0 \mathrm{s}$ and $t=5.0 \mathrm{s} ?$
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