Question
A particular heat engine has a mechanical power output of 5.00 $\mathrm{kW}$ and an efficiency of 25.0$\%$ . The engine expels 8.00 $\times 10^{3} \mathrm{J}$ of exhaust energy in each cycle. Find (a) the energy taken in during each cycle and (b) the time interval for each cycle.
Step 1
We can also express the work done as the difference between the heat energy taken in and the heat energy expelled, i.e., $W = Q_h - Q_c$. Substituting this into the efficiency formula, we get $\eta = \frac{Q_h - Q_c}{Q_h}$. Show more…
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A particular heat engine has a mechanical power output of 5.00 $\mathrm{kW}$ and an efficiency of 25.0$\%$ . The engine expels 8000 $\mathrm{J}$ of exhaust energy in each cycle. Find (a) the energy taken in during each cycle and (b) the time inter- val for each cycle.
A particular engine has a power output of $5.00 \mathrm{~kW}$ and an efficiency of $25.0 \%$. Assuming that the engine expels $8000 \mathrm{~J}$ of energy in each cycle, find (a) the energy absorbed in each cycle and (b) the time for each cycle.
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