Question
A particular heat engine has a useful power output of 5.00 kW and an efficiency of 25.0%. The engine expels 8 000 J of exhaust energy in each cycle. Find (a) the energy taken in during each cycle and (b) the time interval for each cycle.
Step 1
25 and the heat expelled by the engine (QC) is 8000 J. We can use the formula for efficiency to find the heat taken in during each cycle (QH). The formula for efficiency is: \[ \eta = 1 - \frac{QC}{QH} \] Show more…
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A particular engine has a power output of $5.00 \mathrm{~kW}$ and an efficiency of $25.0 \%$. Assuming that the engine expels $8000 \mathrm{~J}$ of energy in each cycle, find (a) the energy absorbed in each cycle and (b) the time for each cycle.
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