00:01
For this problem we have a pendulous that is oscillating around a fixed point, which has a mass of one kilogram.
00:20
Pendulous is oscillating, but we are asked to find at the position of the lowest point of the pendulose, what is the tension of the rope or string that the pendulose is at a position? so we have a free body diagram, we have our mass in g, and we have to compensate, we have a tension force on the rope of the pendulums.
01:04
We also know from the problem data we have the length of the rope, equal to 0 .8 meters.
01:19
So we have our summation of forces in y, we will have tension force minus mg equal zero.
01:40
We also know that in order to have this pendulum moving we will have radial force which is equal to m acceleration, radial acceleration.
01:58
We know that the regular acceleration is b squared by by so this is equal to m a radial acceleration is b squared by r so these two equations can be combined to keep the system in movement and we have that the tension m g is equal to m b squared solving for the tension force is equal to mb squared r plus tension tension based on the values that we have is one mass is one velocity is also given in the problem at the lowest position is equal to 1 .6 test per second...