Question
A person gets into an elevator at the lobby level of a hotel together with his 30 -kg suitcase, and gets out at the 10th floor $35 \mathrm{m}$ above. Determine the amount of energy consumed by the motor of the elevator that is now stored in the suitcase.
Step 1
The formula for potential energy is given by: \[PE = mgh\] where: - \(m\) is the mass of the object (in this case, the suitcase), - \(g\) is the acceleration due to gravity, and - \(h\) is the height to which the object is raised. Show more…
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A person gets into an elevator at the lobby level of a hotel together with his 30-kg suitcase, and gets out at the 10th floor 35 m above. Determine the amount of energy consumed by the motor of the elevator that is now stored in the suitcase.
A person gets into an elevator at the lobby level of hotel together with his 30 kg suitcase and gets out at 10th floor 35 m above. Determine the amount of energy consumed by the motor of the elevator that is now stored in the suitcase.
An elevator ascends from the ground floor to the 10 th floor, a height of $41 \mathrm{~m},$ in $35 \mathrm{~s}$. If the mass of the elevator and passengers is $840 \mathrm{~kg}$, what's the power necessary to lift the elevator? (Your answer is greater than the actual power needed because elevators are counterweighted, thus reducing the work the motor needs to do.)
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