00:02
In this question, we have a hydrogen atom where the electrons in the second excited state, and it absorbs a 320 nanometer photon and one to find the speed of the ionized electron.
00:14
So to solve this problem, that's not a few things.
00:19
So we have a second excited state.
00:35
Okay, this means n is equal to 3.
00:39
Okay, so we need to find the energy of the electron.
00:46
At second excited states which is negative 13 .6, if i buy n square eb and you put n to be 3 and this is one negative 1 .51 ev.
01:11
This is the energy of the electron.
01:13
Next we calculate the energy of the photon.
01:18
This is hc over lambda.
01:23
He put in the numbers.
01:34
And calculate this to be also derived by e.
01:38
Okay, i'm going to get 3 .88 ev...