00:01
For this problem on the topic of electromagnetic waves, we are told that a plain wave with the wavelength of 3 meters is traveling in a vacuum in the positive direction of the x -axis.
00:10
The electric field of amplitude 300 volts per meter is oscillating parallel to the y -axis, and we want to find the frequency, angular frequency, and angular wave number of the wave, the amplitude of the magnetic field component, the axis that is parallel to the magnetic field oscillations.
00:28
We then want to find the time average rate of energy flow in watts per square meter associated with this wave.
00:35
And we are then told that the wave uniformly illuminates the surface of 2 meters square in area.
00:41
And if the surface totally absorbs the wave, we want to know the rate which momentum is transferred to the surface, as well as the radiation pressure that is received by the surface.
00:52
Now, with the wavelength lambda of 3 meters, the frequency from the wave equation, is c over lambda, and this is 2 .998 times 10 to the power 8 meters per second, which is the speed of light and vacuum, over the wavelength of this electromagnetic wave 3 meters, which gives a frequency of 1 times 10 to the power 8 hertz.
01:30
For part b, from the value of the frequency, which we obtained, we can find the angular frequency omega, which is defined to be 2 pi f, and this is 2 pi times the frequency calculated above 1 times 10 to the power 8 hertz, which gives 6 .3 times 10 to the power 8 radiance per second.
01:59
For part c, the angular wave number k is defined as 2 pi over lambda, and this is 2 pi over the wavelength, which we know is 3 meters, which gives the angular wave number to be 2 .1 radiance per meter.
02:34
For part d, we have the electric field amplitude em given to be 300 volts per meter.
02:43
And so the magnetic field amplitude bm is equal to the electric field amplitude over c.
02:52
And so this is 300 volts per meter divided by 2 .998 times 10 to the power 8 meters per second.
03:05
And so we get the magnetic field amplitude to be 1 times 10 to the power minus 6 tesla's...