00:01
So in this question we're asked all about an electric field, which is traveling in the positive x direction and oscillating in the along the y axis.
00:10
And it has a wavelength of three meters and a maximum amplitude of 300 volts per meter.
00:17
Then we're asked numerous questions about this electric field.
00:20
So we're asked first, what is the frequency of the wave? then what is the direction and amplitude of the magnetic field associated with the wave? then what is the wave number and what is the angular frequency of the wave then what is the time average rate of energy flow in watts per meter squared of the wave and then finally if the if the wave falls perfectly on a on a sheet that perfectly absorbs light of area two two meters squared what is the rate of momentum delivered to the sheet and the rate what is the radiation pressure exerted on the sheet.
01:00
So i've written down everything that we're getting.
01:01
So we're given the magnitude is 300 volts per meter.
01:04
The wavelength is 3 meters.
01:05
Speed of light is 3 by 10 to the 8 meters per second.
01:10
The area of the sheet is 2 meters squared.
01:16
And we know that the electric field is of this form.
01:20
So it's of the vector e is equal to the amplitude e0 by sign of kx, where k is the wave number minus omega t, where omega is the angular frequency and we're told that it's in the it's traveling in the positive x direction so then we have the i -hat vector here or unit vector here so for part a to calculate the frequency to start off by calculating the frequency so we know that for any way that the speed of the wave v which is in this case the speed of light c is equal to the frequency by the wavelength so that means that the wavelength is equal to this speed of light divided by the frequency this means that the frequency is equal to the speed of light divided by the wavelength.
02:07
So this is equal to 3 by 10 to the 8 over 3 meters, which is equal to 1 by 10 to the 8 hertz.
02:18
So that's our answer for part 8.
02:19
For part b, we're asked what is the direction and the magnitude of the magnetic field associated with the field? so we know the relationship between the magnitude of the electric and the, the magnitude of the electric and the and the magnetic field is given by e, the magnitude of the electric field over the magnetic field is equal to the speed of light so that implies that our might weather the magnetic field that we're trying to find is equal to the magnitude of the electric field over the speed of light which is equal to 300 volts per meter over 3 right 10 to the 8 meters per second.
03:00
If we work this out this is equal to then is equal to 1 .1 by 10 to the minus 6 tesla.
03:14
And of course, then the direction is and it's in the same direction as e field.
03:22
Since they propagate in the same direction, same direction as the e field.
03:29
So that means it's in the positive x direction.
03:40
So these are answers for part a and b.
03:50
So for part c, we're asked, we're asked at what is the wave number and angular frequency.
03:57
So we know the wave number of the wave is, of any waves, equal 2 pi over the wavelength.
04:03
So this is equal to 2 pi over the lambda, which is equal to 3 meters.
04:07
And if we work this out, this is equal to 2 .09 watts per meter squared...